JoeCMath

Definite vs. Indefinite Integrals

This video goes over the difference between definite (bounded) and indefinite (unbounded) integrals.

Difference Between Definite ($\int$) and Indefinite Integral ($\int_a^b$)

An indefinite integral looks like

\[\int f(x)\,dx.\]

A definite integral looks like

\[\int_a^b f(x)\,dx.\]

Notice, an indefinite integral has no bounds on the integral sign, while a definite integral has a lower bound ($a$) and an upper bound ($b$).

The result of an indefinite integral is a family of functions.

A definite integral gives one number that represents the signed area over the interval from $a$ to $b$.

Watch this section: introduction at 0:00.

Indefinite Integral

The first indefinite integral example in the video is

\[\int x^2\,dx.\]

There are no bounds on the integral sign, so we add a $+C$ to the antiderivative:

\[\int x^2\,dx=\frac{x^3}{3}+C.\]

When we take the derivative of a function, constants disappear, so when we reverse the direction with an indefinite integral, we represent the constant we would gain back with $+C$.

Notice that for any value of $C$

\[\frac{x^3}{3}+C\]

has derivative $x^2$, no matter which constant is chosen.

Watch this section: indefinite integral at 0:21.

Definite Integral

The definite integral example uses the same integrand, but now the integral has bounds:

\[\int_0^1 x^2\,dx.\]

We get the same antiderivative we found for the indefinite integral:

\[\int x^2\,dx=\frac{x^3}{3}.\]

We then evaluate the antiderivative at the top and bottom bounds (based on the Fundamental Theorem of Calculus):

\[\int_0^1 x^2\,dx= \left[\frac{x^3}{3}\right]_0^1.\]

That means

\[\left[\frac{x^3}{3}\right]_0^1 =\frac{1^3}{3}-\frac{0^3}{3} =\frac{1}{3}.\]

The $\frac{1}{3}$ we get represents the signed area under the curve $x^2$ from $x=0$ to $x=1$.

Watch this section: definite integral at 1:15.

The Fundamental Theorem of Calculus

If $F$ is an antiderivative of $f$, then

\[\int_a^b f(x)\,dx=F(b)-F(a).\]

For the video’s example, $F(x)=\frac{x^3}{3}$, $a=0$, and $b=1$, so

\[F(1)-F(0)=\frac{1}{3}-0=\frac{1}{3}.\]

Watch this section: Fundamental Theorem setup at 1:35.

Review From The Video

For an indefinite integral,

\[\int f(x)\,dx=F(x)+C.\]

The result is a collection of functions, and $C$ is an arbitrary constant.

For a definite integral,

\[\int_a^b f(x)\,dx=F(b)-F(a).\]

Geometrically, it represents signed area over the interval from $a$ to $b$.

Watch this section: review at 4:15.

Timestamp Guide

Section Main idea Video
Introduction Compare integral notation with and without bounds. 0:00
Indefinite integral $\int x^2\,dx=\frac{x^3}{3}+C$ gives a family of functions. 0:21
Definite integral $\int_0^1 x^2\,dx$ gives one number. 1:15
Fundamental Theorem Evaluate the antiderivative at the upper and lower bounds. 1:35
WolframAlpha check Compare antiderivative output with shaded signed-area output. 2:53
Review Indefinite integrals return functions; definite integrals return numbers. 4:15

The antiderivative step in this video uses the integration power rule.

For more on why indefinite integrals include $+C$, review the constant of integration notes.

You can also continue with u-substitution or the full JoeCMath integration playlist.